Question

calculate the mass of oxygen is required to completely burn two moles of methane​

Answer 1

Answer:

Explanation:

Balanced chemical equation for combustion of methane as follows.

CH  

4

​  

+2O  

2

​  

→CO  

2

​  

+2H  

2

​  

O

For 1 mole of combustion of methane 2 mole of oxygen are required.

48-gram methane =  

16

48

​  

=3 moles of methane.(Molecular weight of methane is 16)

So, no. of moles of oxygen required will be 6.