Calculate the mass of oxygen obtained by complete decomposition of 10kg of pure potassium chlorate, (k=39,O=16,Cl=35.5)
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2KClO3=2KCl+3O2
Mass of 1 molecule of KClO3=39+35.5+3×16
=39+35.5+48=122.5u
Mass of 2 molecules=122.5×2=245u
Now, 2 molecules of KClO3 give 3O2=3×2×16=96u of oxygen
So 245g of KClO3 gives 96g of O2
10000g (10kg=10000g) KClO3 gives 96×10000/245=3918.36g of O2
Or 3.91836 kg of O2
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