Question

Calculate the mass of oxygen required at STP to convert 2.4g of graphite into carbon
dioxide?
What is orbital? How is it different from Bohr's orbit?
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Answer 1

Answer:

chemical equation for the process is:

C+O2 →CO 2

For the above reaction, 1 mole of O 2

will burn 1 mole of C completely.

In 2.4 g C, number of moles =12

2.4

=0.2 moles of oxygen is required.

Volume occupied by 1 mole of an ideal gas at STP (T=0K and P=1atm) is 22.4L.

Therefore, 0.2 mol O

2

=0.2×22.4 L =4.48L.

Answer 2

Explanation:

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