Calculate the mass of oxygen required at STP to convert 2.4g of graphite into carbon
dioxide?
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chemical equation for the process is:
C+O2→CO2
For the above reaction, 1 mole of O2
will burn 1 mole of C completely.
In 2.4 g C, number of moles = 122.4
=0.2 moles of oxygen is required.
Volume occupied by 1 mole of an ideal gas at STP (T=0K and P=1atm) is 22.4L.
Therefore, 0.2 mol O2
=0.2×22.4 L
=4.48L.
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