calculate the mass of oxygen required at stp to convert 2.4g of graphite into co2
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The equation for the above reaction is as follows:
(graphite is an allotrope of carbon--C)
C + O2 -------> CO2
(s) (g) (g)
Therefore 1 mole of graphite requires 1 Mole of O2 to give 1 mole of CO2
Calculate the moles of graphite:
molar mass of C = 12
mass = 2400 g
moles = mass/molar mass
= 2400/12
=200 moles
if 1 mole of C requires 1 mole of O2
then 200 moles requires = 1 x 200 / 1
= 200 moles
Find mass of oxygen: (molar mass of O2= 32, moles=200)
mass = moles x molar mass
= 200 x 32
= 6400g
= 6.4kg of oxygen
Find the volume of oxygen:
Ideal gas law..... states that 1 mole of an ideal gas occupies 22.4 litres.
therefore 200 moles of O2 occupies= (22.4 x 200) liters
=4480 liters
volume of oxygen = 4480 liters
Explanation:
Explanation:
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