Question

Calculate the mass of oxygen required to burn 14g of C2H4 completely.
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Answer 1

Answer:

see the attachment

Explanation:

hope it helps u!!

Answer 2

Answer:

48 g

Explanation:

Chemical equation :

                                        C₂H₄ + 3 O₂  ⇒  2 CO₂ + 2 H₂O

Now mole ratio :                1           3           2            2    

Moles of C₂H₄ to be burnt = 14 / 28 = 1 / 2 = 0.5 moles

Since 1 moles of C₂H₄ required = 3 moles of O₂ for combustion.

= > 0.5 moles C₂H₄ required = 3 × 0.5 moles O₂ :

= > Mass of oxygen = 3 × 0.5 × 32 g

= >  Mass of oxygen = 96 × 0.5g

= > Mass of oxygen = 48 g

Therefore we get required answer.