Calculate the mass of oxygen required to burn 14g of C2H4 completely.
Answers
Answered by
12
Answer:
see the attachment
Explanation:
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Answered by
17
Answer:
48 g
Explanation:
Chemical equation :
C₂H₄ + 3 O₂ ⇒ 2 CO₂ + 2 H₂O
Now mole ratio : 1 3 2 2
Moles of C₂H₄ to be burnt = 14 / 28 = 1 / 2 = 0.5 moles
Since 1 moles of C₂H₄ required = 3 moles of O₂ for combustion.
= > 0.5 moles C₂H₄ required = 3 × 0.5 moles O₂ :
= > Mass of oxygen = 3 × 0.5 × 32 g
= > Mass of oxygen = 96 × 0.5g
= > Mass of oxygen = 48 g
Therefore we get required answer.
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