Question

Calculate the mass of oxygen required to burn 14g of $C_{2}H_{4}$ completely.

Answer 1

HEYA MATE...
.

C2H4 burns as follows,

C2H4 + 3O2---> 2CO2+ 2H2O

To burn 26 g of C2H4, 96 g of oxygen is reqd.

∴ To burn 14 g of C2H4, 96/26 x 14= 51.7 g of oxygen is reqd.

Therefore, to burn 14 g of C2H4 completely, 51.7 g of O2 is reqd. C2H4 is called Ethene.

Thank u very much.

HOPE THIS HELPS YOU

Answer 2

$to \: burn \: 15gm \: of \: c {2}h4 \\ required \: oxygen \: is$
C2H4 + 3O2 > 2Co2 + 2H2O

14 gram of C2H4 ,

( 96/26 ) × 14 = 51.61

you can write it by round of 51.7 gm of OXYGEN is required to burn C2H4 completely.

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