Question

Calculate the mass of oxygen required to burn 64 gram methane gas

Answer 1

Answer:

mass of Methane = 16 g

mass of 2 molecules of oxygen = 64 g

The equation shows that 16 g of methane requires 64 g of Oxygen

1.61.6g of methane requires 64×1.6/16 = 6.4 g of oxygen

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Answer 2

Answer:

Explanation:

On balancing the combustion eqn u get 1 mole CH4 reacts with 2 mole O2.

So ,4mole CH4 wud react with 8 mole O2. Mass of 8 mole O2 is 256g .