Question

calculate the mass of oxygen that could be required to product enough co with complety reduct1.6g of Fe2o3​

Answer 1

Hello dear

Here in the answer

Reaction of Fe203 with CO is :

Molar mass of fe203 = 160 gram / mole

Molar mass of CO = 28 gram / mole

Now

from the reaction,

:: 160 gram of fe203 reacts with 3 × 28 gram of CO .

:: 1 --------------- 84 / 160 gram of CO .

:: 1.6 kg ------- ( 0.525 ) × 1600 gram of CO .

:: mass of CO which reacts with 1.6 kg of Fe 203 = 840 gram .

Now , reaction to show the formation of carbon monoxide.

2C + O2 ------------- 2CO

from the reaction,

:: 2 Mole of CO is produced by 1 mole off O2 .

:: 2 × 28 gram of CO is what is by 32 gram of O2 .

:: 1 gram of CO is produced by the 32 / 56 gram of O2 .

:: 840 gram of CO is produced by the (4/7 ) × 840 gram of O2 .

480 grams of O2 .

Thus , mass of oxygen that would be required to produce 840 gram CO which completely reduces 1600 gram of Fe203 is 480 Gram .

Hope it helps .