Chemistry, asked by khushir9451, 8 months ago

calculate the mass of ozone which contains the same number of molecules as are present in 5.6ml of sulphur dioxide at STP?

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Answered by Anonymous

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One mole of a gas contains 6.023 x 10^23 constituent particles of the gas and occupies 22.4 L volume.

Therefore, 5.6 L is occupied by 0.25 moles of a gas, which will therefore contain 0.25 x 6.023 x 10^23 particles.

Oxygen gas exists as diatomic molecules (O2), so there are (0.25 x 6.023 x 10^23)

1.50575 * 10^23 molecules of Oxygen gas in 5.6 L.

One molecule contains 2 atoms of oxygen, so the number of atoms is double the number of molecules.

3.0115 * 10^23 atoms of oxygen in 5.6 L oxygen gas.

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calculate the mass of ozone which contains the same number of molecules as are present in 5.6ml of sulphur dioxide at STP?