Calculate the mass of photon of wave length of 3.6 A° ( calculate in SI unit )
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Answered by
552
λ = h / MV
M = h / λV
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M --- mass of proton
h --- planck's constant
λ --- Wave length
V --- Velocity
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λ = 3.6 A⁰ = 3.6 × 10⁻¹⁰ m
h = 6.626 × 10 ⁻³⁴
V = 3 × 10⁸ m/s
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∴ M = ( 6.626 × 10 ⁻³⁴ ) / [ ( 3.6 × 10⁻¹⁰ ) × ( 3 × 10⁸)]
= 6. 135 × 10⁻³³ kg //
M = h / λV
-----------------------------
------------------------------------------------
M --- mass of proton
h --- planck's constant
λ --- Wave length
V --- Velocity
--------------------------------
--------------------------------------------------
λ = 3.6 A⁰ = 3.6 × 10⁻¹⁰ m
h = 6.626 × 10 ⁻³⁴
V = 3 × 10⁸ m/s
---------------------------------
--------------------------------------------------
∴ M = ( 6.626 × 10 ⁻³⁴ ) / [ ( 3.6 × 10⁻¹⁰ ) × ( 3 × 10⁸)]
= 6. 135 × 10⁻³³ kg //
Kimmus:
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Answered by
255
As we know that,
λ = h/p
; h = plank's constant
= 6.626×10⁻³⁴ J-s
p = momentum of proton
= mass× velocity
=m×v
∴λ = h/mv
⇒m = h/λv
v= velocity of light or proton = 3×10⁸ m/s
λ = 3.6 Α° = 3.6×10⁻¹⁰ m
substituting the values
m= (6.626×10⁻³⁴)/(3.6×10⁻¹⁰×3×10⁸)
= 6.135× 10⁻³³ kg
λ = h/p
; h = plank's constant
= 6.626×10⁻³⁴ J-s
p = momentum of proton
= mass× velocity
=m×v
∴λ = h/mv
⇒m = h/λv
v= velocity of light or proton = 3×10⁸ m/s
λ = 3.6 Α° = 3.6×10⁻¹⁰ m
substituting the values
m= (6.626×10⁻³⁴)/(3.6×10⁻¹⁰×3×10⁸)
= 6.135× 10⁻³³ kg
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