Chemistry, asked by mrunalii, 7 months ago

calculate the mass of potassium chlorate required to liberate 6.72 dm cube of oxygen at stp molar mass of potassium chlorate is 122.5g/mol

Answers

Answered by jiya9614

Answer:

According to avogadro's law, 1 mole of every substance occupy 22.4 L at STPand contains avogadro's number of particles. Thus mass of potassium chlorate required to liberate of oxygen at STP will be 24.5 grams.

Answered by Anonymous

Answer:

According to avogadro's law, 1 mole of every substance occupy 22.4 L at STP and contains avogadro's number of particles. Thus mass of potassium chlorate required to liberate of oxygen at STP will be 24.5 grams.

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