Question

Calculate the mass of potassium chlorate required to produce 2.4 gm of oxygen.

[ K=39, Cl = 35.5, O=16]Calculate the mass of potassium chlorate required to produce 2.4 gm of oxygen.

[ K=39, Cl = 35.5, O=16]

please answer..​

Answer 1

Given:

The mass of oxygen produced, m = 2.4 gm

To Find:

The mass of potassium chlorate required to produce the given mass of oxygen.

Calculation:

- The decomposition of Potassium chlorate into oxygen is given as:

2KClO3 + Heat → 2 KCl + 3 O2

- Molar mass of O2 = 16 × 2 = 32 gm

- Molar mass of KClO3 = 39 + 35.5 + 16 × 3 = 122.5 gm

⇒ 3 moles of O2 is produced by 2 moles of KClO3

⇒ Mass of KClO3 required to produce 96 gm of O2 = 2 × 122.5 = 245 gm

⇒ Mass of KClO3 required to produce 2.4 gm of O2 = (245/96) × 2.4

⇒ M = 6.125 gm

- So, the mass of potassium chlorate required to produce 2.4 gm of oxygen is 6.125 gm.

Answer 2

Explanation:

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