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calculate the mass of potassium chlorate required to produce 35 g of potassium chloride on complete decomposition

Answers

Answered by Anonymous
3
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Answer: 57.55 g

Explanation

1. Write the balanced equation

 \mathbb{2KCLO_3 \rightarrow 2KCL + O_2}

2. Calculate the atomic mass

 \rm {2[ 39 + 35.5 + (16 \times 2) \rightarrow 2(39 + 35.5) + 3(32)} \\ \rm2(39 + 35.5 + 48) \rightarrow 2 \times 74.5 + 96 \\ \rm 2 \: \times \: 122.5 \rightarrow 149 + 96 \\ \rm245 \rightarrow 245

3. From the equation we can find that to produce 149 g of KCL we need 245 g of \mathbb{KCLO_3}.

Hence, 149 g of \mathbb{KCL} is produced by \large\bf{245} g of \mathbb{KCLO_3}.

1 g of \mathbb{KCL} is produced by \large \bf \frac{245}{149} g of \mathbb{KCLO_3}.

35 g of \mathbb{KCL} is produced by \large \bf \frac{245}{149} \times 35 = 57.55 g of \mathbb{KCLO_3}.
Answered by Anonymous
8

Reaction :


2 KClO_3\rightarrow 2KCl +O_2


Gram mass of 2 KClO₃


K = 39

Cl = 35.5

O = 16


2 ( 39 + 35.5 + 48 )

= > 2 × 122.5

= > 245



This means that 245 g of potassium chlorate was used .


Now mass of potassium chloride is 2 ( 39 + 35.5 )

= > 2 × 74.5

= > 149 g



Hence 149 g of KCl is produced per 245 g .

1 g is produced per 245 / 148 g

35 g is produced per 245 / 148 g × 35

= > 57.939 g

= > 57.94 g


The mass will be 57.94 g

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