Calculate the mass of potassium chloride required to liberate 6.72 dm3 of oxygen at STP. Molar mass of KClO3 is 122.5 g mol-1
Answers
Answered by
4
Explanation:
KClO3------->KCl+O2
122.5 gm of KClO3 ---------- 22.4lit
x gm of KCl. ---------- 6.72lit
x=(122.5×6.72)÷22.4
=(826.875)÷22.4
=36.9~37g
Similar questions