Question

Calculate the mass of potassium chloride required to prepare its 40% solution in 100 g of water?

Answer 1

Answer:

your ans is here

Explanation:

potessium chloride= Kcl

w2 x 1000

________

M1 x W2

so that mass of Kcl = 60 gm

water = 40 gm

Answer 2

Answer:

$66.6g$ of potassium chloride is required.

Explanation:

Given that,

the mass percentage of solute per mass of the solution is $40$%

We have to figure out the mass $m_1$ of the solute.

$m_2$ (mass of the solvent) $= 100 g$

We know that the mass of the solution is equal to the sum of the mass of the solute and the mass of the solvent.

i.e.  $m=m_1+m_2$

 

Now,

% $\frac{m}{m} =\frac{m_1}{m} *100$

% $\frac{m}{m} =\frac{m_1}{m_1+m_2} *100$

$40=\frac{m_1}{m_1+100}*100\\\\ 40*(m_1+100)=m_1*100$

$40m_1+4000=100m_1\\4000=100m_1-40m_1\\4000=60m_1$

$m_1=\frac{4000}{60} \\m_1=66.6 g$

Hence, $66.6g$ potassium chloride is required.