Question

Calculate the mass of potassium
nitrate obtained by neutralizing a
solution containing 28 g of potassium
hydroxide with nitric acid. (Atomic
mass of nitrogen = 14; potassium = 39;
oxygen = 16 and hydrogen = 1)​

Answer 1

Solution :-

We have :-

• KOH = 28 g

• HNO₃

We know :-

• Molar Mass of KOH = 56

• Molar Mass of HNO₃ = 31

Reaction :-

♦ KOH + HNO₃ ---------⟩ KNO₃ + $\sf{H_2O}$

So one mole KOH Forms one mole KNO₃

⟩⟩ We have 28/56 = ½ moles of KOH

→ ½ mole of KNO₃ is formed

Therefore mass of KNO₃ Formed

= ½ ( 39 + 14 + 16(3) )

= ½ ( 39 + 14 + 48)

= ½ ( 101)

= 50.5 g