Chemistry, asked by Narang3635, 1 year ago

Calculate the mass of potassium sulphate required to prepare its 10 present solution in 1oo gm of water

Answers

Answered by Anonymous
19
by using formula mass of solute/mass of solution into 100

let solute be x

10%s = x/x +10 X 100

10% X 100= x/x+10

10 X ( x + 10) = x

10x + 100 = x

10x - x = 100

9x = 100

x = 100/9

x = 11.1

Hope this helps! Cheers!!
Answered by quratulain
5
A 10% mass solution in 100g of water means x/(100 + x) = 1/10 where x = mass required.
100 + x = 10x
100 = 9x
x = 100/9 = 11.11g of potassium sulphate are required

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