Question

calculate the mass of pure CO2 formed when 500g of magnesium carbonate of 64 % purily dissolves in an excess of HCl as given

MgCO3+ 2HCl ----> MgCl2 + H2O + CO2

ANSWER IT FAST.....​

Answer 1

Answer:

Explanation:

as purity of mgco3 is 64 percent

therefore reacted / total will be  0.64

reacted/500=0.64

reacted = 320 g

moles of mgco3 = 320/84

=3.809

moles of co2 = 3.809

mass of pure co2 =167.619