Question

Calculate the mass of salt produced when 0.2 m 100ml of h2so4

Answer 1

We know, equivalent weight = molar mass / basicity

Basicity of sulphuric acid is two.

So 1 mol H2SO4 = 2 equivalent

Therefore 1 M H2SO4 = 2N H2SO4

Now, 100 ml of 0.2M H2SO4 ≡ 100X0.2 ml of 1 M H2SO4

≡ 20 ml of 2 N H2SO4

≡ 20X2 ml of 1N H2SO4

≡ 40 ml of 1N H2SO4

And

1M NaOH = 1 N NaOH

So, 100 ml of 0.2 M NaOH ≡ 100X0.2 ml of 1M NaOH

≡ 20 ml of 1N NaOH

When acid and base are mixed, neutralisation will occur to produce salt and water.

20 ml of 1N NaOH ≡ 20 ml of 1N H2SO4

Rest acid = 20 ml 1N H2SO4,

Final volume of the solution is 200 ml.

If final strength of acid is S then

20 ml X 1N=200 ml X S

Or, S= 0.1 N

Final normality of the solution is 0.1N