Question

. Calculate the mass of salt that can be obtained from the reaction of 240g of sodium hydroxide with an excess amount of sulphuric acid.

Answer 1

Answer:

392gm

Explanation:

Given,

compounds are - NaOH and H2SO4

NaOH = Na+O+H = 23+16+1 = 40 amu

H2SO4 = (H)2 + S + (O)4 = 2+32+64= 98 amu

Thus,

the reaction =

NaOH + H2SO4 ---------> Na2SO4 + H2O

the no. of moles of NaOH =

weight / molecular.weight = 240/40 = 4 moles.

Since,

the ratio = 1 : 1 between Na2SO4 and NaOH

therefore,

moles = weight /molecular weight

weight = moles × molecular weight = 4× 98 = 392gm.