Question

calculate the mass of so3 product if 500 gram SO2 react with 200 gram O2 according equation to SO2 gas + O2 gas gives to so3 gas identify the limitinreagent
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Answer 1

Answer:

the limiting reagent will be o₂

Explanation:

when we balance the following equation we get 2SO₂ + O₂ -> 2SO₃

which means that in the reaction o₂ is less in this reaction and will exhaust completely . therefor , 0₂ is the limiting reagent

hope it helps ... :)

Answer 2

Answer:

Answer: Mass of SO3 Gas formed: 1000 g

Explanation:

First Write the Equation in its Balanced form -

2SO3 + O2 = 2SO3

Then, We check the Limiting Reagent.

It comes out to be O2 gas.(Check Limiting Reagent by Given Moles÷St. Coefficient,

the Reactant with Least Value will be the Limiting Reagent)

The Value of Given Moles÷St. Coefficient for O2 will come 6.25.

Now Multiply the Value(6.25) to the St. Coefficient of the Product required.(Here 2 SO3)

So, We get, 6.25 x 2 = 12.5 moles of SO3 gas.

To find Mass of SO3, Multiply Moles to its Molecular Weight.

12.5 x 80

You Get ANSWER: 1000g of SO3 Gas