Question

calculate the mass of SO3 prodused when 500g of SO2 react with200g of O2 according to the equation 2SO2+O2-->2SO3
identify limiting reagent​

Answer 1

Explanation:

2SO

2

+O

2

→SO

3

Here the mole ratio between S0

2

and SO

3

is 2:2 = 1.

Here we used 2 g of SO

2

, so we need to convert that amount into moles.

Sulphur dioxide has molar mass of 64 g/mol. So,

64g/mol

2g

= 0.03125 mol of SO

2

Sulphur trioxide has molar mass of 80 g/mol. So,

0.03125 mol. 80 g/mol = 2.5 g of SO

3

Sp, 2.5 grams of sulphur trioxide was produced.

Answered By