Calculate the mass of sodium acetate (CH3COONa) required to make 500 mL of 0.375 molar aqueous solution. Molar mass of sodium acetate is 82.0245 g mol –1
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molarity=weight of solute x 1000/molar weight of solute x volume of solution.
0.375=weight of CH3COONa x1000/82 x 500
weight of CH3COONa=41 x 0.375 g
=15.375 g
0.375=weight of CH3COONa x1000/82 x 500
weight of CH3COONa=41 x 0.375 g
=15.375 g
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