Calculate the mass of sodium acetate (CH3COONa) required to make 500 mL of 0.375 molar aqueous solution. Molar mass of sodium acetate is 82.0245 g mol–1
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Molarity = [W / (GMW)] × [1000 / Volume in ml]
W = Molarity × GMW × Volume in ml / 1000
= 0.375 mol/L × 82.0245 g/mol × 500mL / 1000
= 15.38 × 10⁻³ g
= 15.38 mg
Mass of sodium acetate required is 15.38 mg
W = Molarity × GMW × Volume in ml / 1000
= 0.375 mol/L × 82.0245 g/mol × 500mL / 1000
= 15.38 × 10⁻³ g
= 15.38 mg
Mass of sodium acetate required is 15.38 mg
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