Question

Calculate the mass of sodium acetate required to make 200 ml of 0.245 molar aqueous solution consider the molar mass of sodium acetate is 82

Answer 1

Answer:

4.018 g

Explanation:

Molarity (M) = 0.245

Volume (V in mL) = 200 mL

Molecular Weight (MW) = 82

Mass (x) = ?

M = x * 1000 / MW * V in mL

0.245 = x * 1000 / 82 * 200

After calculation, x = 4.018 g

Answer 2

mass of sodium acetate required to make 200 ml of 0.245 molar aqueous solution is 4.018g

Explanation:×

Given Molarity (M) = 0.245 molar,

Volume (V in mL) required = 200 ml

Molar mass of sodium acetate= 82

Mass (x) of sodium acetate = To be calculated

M = x  × 1000 / MW × V in mL

0.245 = x  × 1000 / 82 × 200  

On calculation, we get mass of sodium acetate x = 4.018 g