Question

calculate the mass of sodium acetate required to make 500 ml of 0.375 molar aqueous solution .molar mass of sodium acetate is 82.0245 g mol​

Answer 1

Answer:

15.375

Explanation:

molar mass = 82.02

required mass = 0.375/2 multiply by 82.02= 15.375

Answer 2

Answer:

15.38 g

Explanation:

0.375 M aqueous solution of sodium acetate

                            = 1000ml of solution containing 0.375 moles of CH3COONa

Therefore, No. of moles of CH3COONa in 500ml = 0.375 ÷ 1000 x 500

                                                                                  = 0.1875

Molar mass = 82.0245 g/mol

Therefore, Required mass of sodium acetate = (No. of moles) x Molar mass

                                                                           = 0.1875 x 82.0245

                                                                           = 15.38 g