calculate the mass of sodium acetate required to make 500ml of 0.375 molar aqueous solution
Answers
Answered by
11
0.375 M aqueous solution of sodium acetate means that 1000 mL of solution containing 0.375 moles of sodium acetate.
∴No. of moles of sodium acetate in 500 mL = (0.375/1000)×500 = 0.375/2 = 0.1875
Molar mass of sodium acetate = 82.0245g mol-1
∴Mass of sodium acetate acquired = 0.1875×82.0245 g = 15.380g
I hope you understand.
Attachments:
![](https://hi-static.z-dn.net/files/da6/bfaa2ddcb01096761970df1880928c51.jpg)
Similar questions