Question

Calculate the mass of sodium chloride required to prepare its 25% (mass percent) solution in 200g of
water.​

Answer 1

66g

Explanation:

let mass of nacl required be x.

then, 25 % of nacl should be there in the solution of x g nacl and 200g water

Answer 2

The mass of sodium chloride required to prepare its 25% (mass percent) solution in 200g of water is 66.66 g.

Explanation:

Given,

Mass of water = 200g

We have to find the mass of sodium chloride required to prepare its 25% of solution.

Let the mass of sodium chloride required be $x$ g

The mass of solution = $(x+200)g$

$x$ g of solute in $(x + 200)g$ of solution

⇒ $25\% = \frac{x}{x + 200}$

⇒ $25 = \frac{x}{x + 200} \times 100$

⇒ $25\times x + 25\times200 = x\times 100$

⇒ $25x + 5000 = 100x$

⇒ $100x - 25x = 5000$

⇒ $75x = 5000$

⇒ $x = \frac{5000}{75}$

⇒ $x = 66.66$

Hence, the mass of sodium chloride required to prepare its 25% (mass percent) solution in 200g of water is 66.66 g.

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