Question

Calculate the mass of sodium chloride required to prepare it's 20%(mass percent) solution in 100 g of water.​

Answer 1

$\huge \underline \bold \red {AnSwer :-}$

Let the mass of sodium sulphate required be =xg

The mass of solution =(x+100)g

x g of solute in (x + 100) g of solution

$⟹$20% = $\frac{x}{x + 100} \times 100$

$⟹$20x+2000=100x

$⟹$80x=2000

$⟹$ x= $\frac{2000}{80}$ =25 g