Question

Calculate the mass of sodium formate (HCOONa) required to make 400 ml of 0.475 molar aqueous solutions.​

Answer 1

Answer:

15.38 g

Step by step explanation:

0.375 M solution of CH3COONa = 0.375 moles of CH3COONa/1000ml

No. of moles of CH3COONa in 500ml = 0.375/1000 × 500 = 0.1875 moles

Molar mass of sodium acetate = 82.0245 g/mole

∴ mass of CH3COONa required = 82.0245 × 0.1875 = 15.38g