Question

Calculate The mass of sodium hydroxide obtant by the reaction of 2.3gram sodium with excess water

Answer 1

Explanation:

⭐SOLUTION⭐

reaction is...

2 Na + H2O ➡ 2 NaOH + H2

2.3 g

mole of Na = 2.3/23=0.1

according to the equation,

2 mole of Na will form 2 mol of NaOH.

so, 0.1 mol of Na will form 0.1 mol of NaOH...

so, 0.1 mole of NaOH= 0.1 × 40

= 4 gram

so, 2.3 gram of Na will give 4 gram of NaOH....

hope it helps......✌✌

Thank you