calculate the mass of sodium nitrate obtained when58.9g nitrate. allowed to heat
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we know
Na + NO3 ➡NaNO3
(23g) (62g) (85g)
here 62 g of nitrate reacts with of Na to give 85g sodium nitrate
1 g of nitrate reacts with Na to give 85/62 g of sodium nitrate
58.9g of nitrate reacts with Na to give (85/62 × 58.9) g sodium nitrate
hence amount of sodium nitrate formed is 80.75 g
Na + NO3 ➡NaNO3
(23g) (62g) (85g)
here 62 g of nitrate reacts with of Na to give 85g sodium nitrate
1 g of nitrate reacts with Na to give 85/62 g of sodium nitrate
58.9g of nitrate reacts with Na to give (85/62 × 58.9) g sodium nitrate
hence amount of sodium nitrate formed is 80.75 g
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