calculate the mass of sodium sulphate required to prepare its 20 solution in 100 gram of water
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Mass % of sodium sulphate in the solution = 20%
If the total mass of the solution = 100g
Then mass of sodium sulphate = (20/100)x100 = 20g
Mass of water = 100-80= 20g
HOPE THE ANSWER HELP!!!
If the total mass of the solution = 100g
Then mass of sodium sulphate = (20/100)x100 = 20g
Mass of water = 100-80= 20g
HOPE THE ANSWER HELP!!!
2003tagore:
super bro
Answered by
1
Let the mass of sodium sulphate required be ' x ' g
The mass of water = 100 g
The mass of solution = ( mass of sodium sulphate + mass of water ) = ( x + 100 ) g
Percentage of sodium sulphate in solution = ( Mass of sodium sulphate / Mass of solution ) * 100
20 = [ x / ( x + 100 ) ] * 100
20x + 2000 = 100x
80x = 2000
x = 2000 / 80
x = 25 g
THEREFORE , THE MASS OF SODIUM SULPHATE REQUIRED IS 25 G.
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