Chemistry, asked by sgaileandat9874, 8 months ago

Calculate the mass of Sodium Sulphate required to prepare its 10% (mass percent) solution in 45 g of water.

Answers

Answered by admoh468
10

Answer:

Explanation:

Mass of the solution = mass of solute + mass of solvent

Given that the mass percent of sodium sulphate solution is 20%.

Let the mass of sodium sulphate which is required to prepare this solution be x grams.

Given that the mass of water is 100 g.

So,

20 = [x/(x + 100)] * 100

20/100 = [x/x + 100]

1/5 = x/x + 100

x + 100/5 = x

x + 100 = 5x

5x - x = 100

4x = 100

x = 100/4

x = 25

Thus, 25g of sodium sulphate is required.

hope it helps u

plz mark as brainlist answer

Answered by asmitaroy631
1

Explanation:

According to the question the mass percentage of sodium sulphate is 20%.

mass of water is 100g

:. let the mass of sodium sulphate be X.

or,20=X/(X+100)x100

or,20/100=X/(X+100)

or,1/5=X/(X+100)

or,X+100/5=X

or,X+100=5x

or,5x-x=100

or,4X=100

or,X=100/4

or,X=25 g

Similar questions