Calculate the mass of Sodium Sulphate required to prepare its 10% (mass percent) solution in 45 g of water.
Answers
Answered by
10
Answer:
Explanation:
Mass of the solution = mass of solute + mass of solvent
Given that the mass percent of sodium sulphate solution is 20%.
Let the mass of sodium sulphate which is required to prepare this solution be x grams.
Given that the mass of water is 100 g.
So,
20 = [x/(x + 100)] * 100
20/100 = [x/x + 100]
1/5 = x/x + 100
x + 100/5 = x
x + 100 = 5x
5x - x = 100
4x = 100
x = 100/4
x = 25
Thus, 25g of sodium sulphate is required.
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Answered by
1
Explanation:
According to the question the mass percentage of sodium sulphate is 20%.
mass of water is 100g
:. let the mass of sodium sulphate be X.
or,20=X/(X+100)x100
or,20/100=X/(X+100)
or,1/5=X/(X+100)
or,X+100/5=X
or,X+100=5x
or,5x-x=100
or,4X=100
or,X=100/4
or,X=25 g
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