Question

calculate the mass of sodium sulphate required to prepare 20 percent solution in 100g of water​

Answer 1

Brainly.in

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Secondary SchoolChemistry 5+3 pts

Calculate the mass of sodium sulphate required to prepare 20 percent solution in 100g of water​

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Saurabh8115 · Helping Hand

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sofiumer87

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Let the mass of sodium sulphate required be = x g

The mass of solution would be = (x +100) g

x g of solute in (x + 100) g of solution

20% = ×/x+100 x100

20 x + 2000= 100 x

80 x = 2000

x = 2000/ 80

= 25 g

Answer 2

$\huge\sf\pink{Answer}$

☞ 25 Grams

$\rule{110}1$

$\huge\sf\blue{Given}$

✭ 20 % ( Mass percent ) Solution in 100 g of water?

$\rule{110}1$

$\huge\sf\gray{To \:Find}$

◕ The mass of Sodium Sulphate required to prepare it

$\rule{110}1$

$\huge\sf\purple{Steps}$

❍ Let's us take the Mass of Sodium Sulphate that is required to make

❍ 20 % (Mass percent ) Solution in 100 g of water be y grams

That is,

➝ Mass of Sodium Sulphate = y grams

So,

➝ The Mass of the entire Solution be ( 100 + y ) grams

Since,

Solution = Solute + Solvent

Here,

➳ Solute = Sodium Sulphate ( Na₂SO₄ )

➳ Solvent = Water ( H₂O )

So

☆ y grams of solute in ( y + 100 ) grams of solution

Given that,

20 % ( Mass percent ) Solution in 100 g of Water

Therefore,

$\sf \dashrightarrow 20 \ \%=\dfrac{y}{y+100} \times 100$

$\sf \dashrightarrow 20y+2000=100y$

$\sf \dashrightarrow 80y=2000$

$\sf \dashrightarrow y=\dfrac{2000}{80} \ g$

$\sf \dashrightarrow y=25 \ g$

$\orange{\dashrightarrow{\sf Mass=25 \ grams}}$

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