Chemistry, asked by gsrilatha10, 11 months ago

Calculate the mass of sodium sulphate required to prepare 30% of its solution in 140 grams of water

Answers

Answered by punkydoodle818
1

Answer: x = 25

Thus, 25g of sodium sulphate is required

Explanation:

Mass of the solution = mass of solute + mass of solvent

Given that the mass percent of sodium sulphate solution is 20%.

Let the mass of sodium sulphate which is required to prepare this solution be x grams.

Given that the mass of water is 100 g.

So,

20 = [x/(x + 100)] * 100

20/100 = [x/x + 100]

1/5 = x/x + 100

x + 100/5 = x

x + 100 = 5x

5x - x = 100

4x = 100

x = 100/4

x = 25

Thus, 25g of sodium sulphate is required.

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