Calculate the mass of sodium sulphate required to prepare 40%(mass per cent ) solution in 250 g of water
Answers
Answered by
0
Answer:
500/3
Explanation:
hey, now see...for this question the knowledge of atomic masses of constituents is not required
"mass of solute/mass of solution*100= Mass percent"
here; mass %= 40%
Let mass of solute be x
Mass of solution= 250+x
substituting the values:
(x/250+x)*100= 40
x= (40/100)* (250+x)
x= [(2/5)(250)]+ [(2/5)(x)]
x- 2x/5 = 100
3x/5= 100
x= 500/3
Hence the mass of sodium sulphate required is 500/3 grams.
Similar questions