Calculate the mass of sodium sulphate required to prepare it's 20% (mass 20%) solution in 100g of water...... Please answer me fast..... Explain it also.....
Answers
Answered by
75
Hey friend,
here is the answer to your question
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.
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mass by mass percentage = (mass of solute / mass of solution) × 100
So,mass of the solution = mass of solute + mass of solvent
given, mass percent of sodium sulphate solution is 20 %.
Let the mass of solute ( sodium sulphate) which is required to prepare this solution be x g.
mass of water is 100 g.
So,
20 = [x / (x + 100)] × 100
Solve x and you will get the answer.
x= 25.
hope this will help.
here is the answer to your question
.
.
.
mass by mass percentage = (mass of solute / mass of solution) × 100
So,mass of the solution = mass of solute + mass of solvent
given, mass percent of sodium sulphate solution is 20 %.
Let the mass of solute ( sodium sulphate) which is required to prepare this solution be x g.
mass of water is 100 g.
So,
20 = [x / (x + 100)] × 100
Solve x and you will get the answer.
x= 25.
hope this will help.
Answered by
28
Plase mark me as the brainliest....please...
Let the mass of sodium sulphate required be =xg
The mass of solution =(x+100)g
x g of solute in (x + 100) g of solution
20% =xx+100×100
20x+2000=100x
80x=2000
x=200080
=25g
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