Chemistry, asked by Rajes2330, 1 year ago

Calculate the mass of sodium sulphate required to prepare it's 20% (mass 20%) solution in 100g of water...... Please answer me fast..... Explain it also.....

Answers

Answered by AryanDeo
75
Hey friend,
here is the answer to your question
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.
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mass by mass percentage = (mass of solute / mass of solution) × 100

So,mass of the solution = mass of solute + mass of solvent

given, mass percent of sodium sulphate solution is 20 %.

Let the mass of solute ( sodium sulphate) which is required to prepare this solution be x g.
mass of water is 100 g.

So,
20 = [x / (x + 100)] × 100
Solve x and you will get the answer.

x= 25.

hope this will help.


Answered by salonishrimali
28

Plase mark me as the brainliest....please...

Let the mass of sodium sulphate required be =xg


The mass of solution =(x+100)g


x g of solute in (x + 100) g of solution


20% =xx+100×100


20x+2000=100x


80x=2000


x=200080


=25g

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