Question

Calculate the mass of sodium Sulphato
required to prepare it's 20percent (Mass percent )
solution in 100g of water?​

Answer 1

$\bigstar$ Answer $\bigstar$

$\checkmark$ To Find:

The mass of Sodium Sulphate required to prepare its

20 % ( Mass percent )  Solution in 100 g of water?​

$\checkmark$ Solution:

According to the Question,

We are asked to Find the Mass of Sodium Sulphate

Let us take the Mass of Sodium Sulphate that is required to make

20 % (Mass percent )  Solution in 100 g of water be y grams

i.e.,

⇒ Mass of Sodium Sulphate = y grams

So,

⇒ The Mass of the entire Solution be ( 100 + y ) grams

Since,

Solution = Solute + Solvent

Here,

→ Solute = Sodium Sulphate ( Na₂SO₄ )

→ Solvent = Water ( H₂O )

Therefore,

y grams of solute in ( y + 100 ) grams of solution

Given that,

20 % ( Mass percent ) Solution in 100 g of Water

Therefore,

$\green{\sf \implies 20 \ \%=\dfrac{y}{y+100} \times 100}$

$\blue{\sf \implies 20y+2000=100y}$

$\red{\sf \implies 80y=2000}$

$\purple{\sf \implies y=\dfrac{2000}{80} \ g}$

$\pink{\sf \implies y=25 \ g}$

$\orange{\boxed{\boxed{\sf Mass=25 \ grams}}}$

Hence,

The mass of Sodium Sulphate required to prepare its

20 % ( Mass percent )  Solution in 100 g of Water is

25 grams

So,

Mass of Sodium Sulphate = 25 g