Chemistry, asked by anujsinghtomar5353, 11 months ago

Calculate the mass of sodium which contain same number of atoms as are present in 15 g of calcium

Answers

Answered by NILESH0KR
53

Mca= 15g

moles, n= 15/40= 3/8

no. of atom of Ca= 3/8 * 6.67* 10^23

Now,

no. of Na atom= 3/8*6.67 * 10^23

moles of Na = 3/8

mass of Na= 3/8*23 =8.6

Answered by AyuBhai94
1

Answer:

Moles Ca = 4 g / 40 = 0.,1

= moles Na  

Mass Na = 0.1 mol x 23 g/mol = 2.3g

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