Calculate the mass of sodium which contain same number of atoms as are present in 15 g of calcium
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Answered by
53
Mca= 15g
moles, n= 15/40= 3/8
no. of atom of Ca= 3/8 * 6.67* 10^23
Now,
no. of Na atom= 3/8*6.67 * 10^23
moles of Na = 3/8
mass of Na= 3/8*23 =8.6
Answered by
1
Answer:
Moles Ca = 4 g / 40 = 0.,1
= moles Na
Mass Na = 0.1 mol x 23 g/mol = 2.3g
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