Question

Calculate the mass of sodium which contains the same no of stoms as sre present in 15g of Ca

Answer 1

$\large\underline{\underline{\sf Solution:}}$

$\large{\boxed{\sf Moles(n)=\frac{Mass}{Moleculer\:Mass} }}$

$\large\implies{\sf Mole\:of\:Ca=\frac{15}{40} }$

$\large\implies{\sf 0.375 mol}$

$\large{\sf Mass\:of\:Na=0.375×23}$

$\large\implies{\sf 8.625g}$

$\Large\underline{\underline{\sf Answer:}}$

•°• Mass of sodium is 8.625 g .

Answer 2

Answer:

Moles Ca = 15 g / 40 = 0.375

= moles Na

Mass Na = 0.375 mol x 23 g/mol = 8.6 g

Explanation: