Question

calculate the mass of sugar required to prepare its 10% solution in 250 g of solution...and how plz explain

Answer 1

By applying the formula,
mass percentage (10%)=mass of solute(sugar)×100/mass of solution (250g)

we can find the mass of solute (sugar).
IF YOU NOT SATISFIED WITH MY ANSWER,PLZ comment on my answer after that I SOLVE IT....

Answer 2

Answer:

25 grams of sugar is required to prepare its 10% solution in 250 g solution.

Explanation:

10% solution means that 10 g of solute ion 100 grams of solution.

Here we are have to prepare 250 grams of sugar solution which should be of 10%.

Required percentage of sugar solution,(w/w %) = 10%

Mass of the solute = x

Mass of the solution = 250 g

$w/w\%=\frac{\text{Mass of solute}}{\text{Mass of solution}}\times 100$

$10\%=\frac{x}{250 g}\times 100$

x = 25 g

Mass of solution =  Mass of solute + Mass of solvent

Mass of solvent = 250 - 25 g = 225 g

We need 25 grams of sugar which we will be dissolving in 225 grams of water to prepare 10% sugar solution.