Calculate the mass of sugar to prepare tm aqueous solution in 2l of water
Answers
Answered by
5
given element by its atomic mass.
12 X 12.01 g/mol = 144.12 g/mol C
22 X 1.008 g/mol = 22.176 g/mol H
11 X 16.00 g/mol = 176.00 g/mol O
Total = 342.296 ~ 342.30 g/mol C12H22O11
These numbers can be found using the periodic table
The second step is to take the number of grams of sugar you have; in this case 20g and divide it by the molar mass of the sugar 342.30 g/mol.
20g = 0.058 mol C12H22O11
342.30g/mol
The Third step is to take the number of moles and divide it by your total volume of 2L. Remember that for liquid concentrations, it is always in units of moles/L; this is also the definition of Molarity.
0.058 mol = 0.029 mol/L OR 0.029M C12H22O11
2L
I hope this clears up any confusion.
12 X 12.01 g/mol = 144.12 g/mol C
22 X 1.008 g/mol = 22.176 g/mol H
11 X 16.00 g/mol = 176.00 g/mol O
Total = 342.296 ~ 342.30 g/mol C12H22O11
These numbers can be found using the periodic table
The second step is to take the number of grams of sugar you have; in this case 20g and divide it by the molar mass of the sugar 342.30 g/mol.
20g = 0.058 mol C12H22O11
342.30g/mol
The Third step is to take the number of moles and divide it by your total volume of 2L. Remember that for liquid concentrations, it is always in units of moles/L; this is also the definition of Molarity.
0.058 mol = 0.029 mol/L OR 0.029M C12H22O11
2L
I hope this clears up any confusion.
Answered by
0
Explanation:
ɪ ʜᴏᴘᴇ ɪᴛ ᴡɪʟʟ ʙᴇ ʜᴇʟᴘғᴜʟ......
Attachments:
Similar questions