Question

calculate the mass of sulfur dioxide produced by burning 16 g of sulfur in excess of oxygen in contact process. ( Average atomic mass : S =32 u, O = 16 u) ​

Answer 1

Answer:

Explanation:

Moles S=16g/32g/mol=0.5

Moles 02 needed =0.5

mass 02=0.5mol×32g/mol=16g

Moles SO2 produced =0.5

mass SO2=0.5mol×64g/mol=32g

Answer 2

The mass of sulfer dioxide is 48 unit

Explanation:

S+ O2= SO2

1 mole of sulfur and 1 mole of oxygen reacts and make one mole of sulfur dioxide.

As given,  atomic mass : s=32 unit  o= 16 unit

therefore the atomic mass of so2= 32+(16*2)

                                                       = 64 unit

now if we say that we will use 16g of sulfer

then the atomic mass of so2= 16+(16*2)

                                                       = 48 unit

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