Calculate the mass of sulphur dioxide produced by burning 16 gram of sulphur in excess of oxygen in contact process
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1 mole of sulphur reacts with one mole of Oxygen to give one mole of Sulphur dioxide and number of moles in 16 grams of sulphur is 16 by 32 which is equal to .5 moles so point .5 moles of Sulphur dioxide is formed and molecular mass of Sulphur dioxide is 64 and therefore the weight of the Sulphur dioxide producers 64×.5=32gm Sulphur dioxide is produced
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