Question

Calculate the mass of the following a) 2 molecules of waterb) 2 moles of carbon dioxide * 36g and 88g 18g and 22g 18g and 44g 36g and 44g​

Answer 1

Answer:

CH  

4

​  

(g)+2O  

2

​  

(g)→CO  

2

​  

(g)+2H  

2

​  

O(g)

Since 1 mole methane = 12+4×1=16 g and 2 mole oxygen =2×32=64 g, 1 mole CO  

2

​  

=12+32=44 g and 2 mole water=2×18=36 g

From the balanced reaction: One mole(or 1 molecule or 16 g) of CH  

4

​  

 reacts with 2 moles (or 2 molecules or 64 g) of oxygen to give one mole (or 1 molecule or 44 g) of CO  

2

​  

 and 2 mole (or 2 molecules or 36 g) of water.

For the gaseous system at STP:

22.4 L methane reacts with 44.8 L of oxygen to give 22.4 L of CO  

2

​  

 and 44.8 L of water.

Explanation: