Question

calculate the mass of the following two moles of carbon dioxide and 6.022 × 10^ 23 molecules of carbon dioxide. plz answer me correctly... ​

Answer 1

Answer:

Explanation:

As given:

no of moles = 2

no of molecules = 6.02 * 10^23 molecules

To find out:

Mass of 2 moles of CO2=?

Solution:

Formula being used here:

No of Moles= given mass/molar mass

Molar mass of CO2 is  44 g/mol

So,

Mass= no of moles * no of moles

Putting values:

Mass=  2 * 44

Mass= 88 g

So,the mass of two moles of CO2 is 88 g

HAVE A GREAT DAY MATE :)

Answer 2

$\Huge\underline{\underline{\sf Answer}}$

$\large\underline{\underline{\sf Mass\:of\:2\:mole\:of\:CO_2\:is\:88g}}$

And

$\large\underline{\underline{\sf Mass\:of\:CO_2\:in\:6.023×10^{23}}}$

$\large\underline{\underline{\sf molecule\:is\:44g}}$

$\Huge\underline{\underline{\sf Solution}}$

$\large\underline{\underline{\sf Given:}}$

• No. of Molecule = $\sf{6.023×10^{23}}$

• Molecular mass of ($\sf{CO_2}$)=44g

• No. of moles of $\sf{CO_2}$=2 moles

$\large\underline{\underline{\sf To\:Find:}}$

• Mass of 2 moles of $\sf{CO_2}$=?

• Mass of $\sf{CO_2}$ in $\sf{6.023×10^{23}\: molecule}$=?

_________________________________________

Mass of Carbon Dioxide in 2 mole :-

We know that :-

$\large{\boxed{\sf Mole(n)=\frac{Mass(m)}{Molecular\:Mass(M_w)}}}$

$\large\implies{\sf Mass(m)=n×M_w }$

$\large\implies{\sf m=2×44}$

$\large\implies{\sf m=88g}$

Hence ,

$\large\underline{\underline{\sf Mass\:of\:2\:mole\:of\:CO_2\:is\:88g}}$

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Mass of Carbon Dioxide in 6.023×10^23 molecules :-

We know that

$\sf{6.023×10^{23}}$ = 1 mole

and

1 mole of $\sf{CO_2}$=44g

Therefore

$\large\underline{\underline{\sf Mass\:of\:CO_2\:in\:6.023×10^{23}}}$

$\large\underline{\underline{\sf molecule\:is\:44g}}$