Question

Calculate the mass of the Oxygen required to combustion of 48g of Carbon? (Mass of C =12g, O =1​

Answer 1

Answer:

(i) 1 mole of carbon is burnt in air.

C+O2→CO2

1 mole of C produces 1 mole of CO2 which corresponds to 44 g of CO2.

(ii) 1 mole of carbon is burnt in 16 g of dioxygen.

16  g of dioxygen corresponds to 3216=0.5 moles.

Here, dioxygen is the limiting reagent.

It will produce 0.5 moles of CO2 which corresponds to 0.5×44=22 g of CO2.

(iii) 2 moles of carbon are burnt in 16 g of dioxygen.

16  g of dioxygen corresponds to 3216=0.5 moles.

Here, dioxygen is the limiting reagent.

It will produce 0.5 moles of CO2 which corresponds to 0.5×44=22 g of CO2.

Explanation:

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Answer 2

Answer:

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