Calculate the mass of the product that would be formed when 2000cm3 of hydrogen chloride gas reacts completely with excess ammonia gas (H=1,O;N=14.0,C1=35.5,one mole of gas occupied 24L at room temperature and pressure)
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Answer:
mole occupies 22.4L volume
∴ moles of NH3 present= 22.467.2=3
(ii) 1 mole of NH3 reacts with 1 mole of HCl to give 1 mole of NH4Cl. Here only 1 mole of HCl & 3moles of NH3 are present. Hence, 1 mole of NH4Clis produced.
Mass of NH4Cl produced= 1× Molecular mass
=1×(14+4×1+35.5)
=53.5g
(iii) Here NH3 is present in excess than what is required to react with 1 mole HCl. Hence 3−1=2moles of NH3 will remain after completion of the reaction.
(iv) Chemical reaction involved is:
NH3+HCl⟶NH4Cl .
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